下面列出了怎么用org.springframework.test.context.junit4.rules.SpringMethodRule的API类实例代码及写法，或者点击链接到github查看源代码。
private static void ensureSpringRulesAreNotPresent(Class<?> testClass) {
for (Field field : testClass.getFields()) {
Assert.state(!SpringClassRule.class.isAssignableFrom(field.getType()), () -> String.format(
"Detected SpringClassRule field in test class [%s], " +
"but SpringClassRule cannot be used with the SpringJUnit4ClassRunner.", testClass.getName()));
Assert.state(!SpringMethodRule.class.isAssignableFrom(field.getType()), () -> String.format(
"Detected SpringMethodRule field in test class [%s], " +
"but SpringMethodRule cannot be used with the SpringJUnit4ClassRunner.", testClass.getName()));
}
}
private static void ensureSpringRulesAreNotPresent(Class<?> testClass) {
for (Field field : testClass.getFields()) {
Assert.state(!SpringClassRule.class.isAssignableFrom(field.getType()), () -> String.format(
"Detected SpringClassRule field in test class [%s], " +
"but SpringClassRule cannot be used with the SpringJUnit4ClassRunner.", testClass.getName()));
Assert.state(!SpringMethodRule.class.isAssignableFrom(field.getType()), () -> String.format(
"Detected SpringMethodRule field in test class [%s], " +
"but SpringMethodRule cannot be used with the SpringJUnit4ClassRunner.", testClass.getName()));
}
}
private static void ensureSpringRulesAreNotPresent(Class<?> testClass) {
for (Field field : testClass.getFields()) {
if (SpringClassRule.class.isAssignableFrom(field.getType())) {
throw new IllegalStateException(String.format("Detected SpringClassRule field in test class [%s], " +
"but SpringClassRule cannot be used with the SpringJUnit4ClassRunner.", testClass.getName()));
}
if (SpringMethodRule.class.isAssignableFrom(field.getType())) {
throw new IllegalStateException(String.format("Detected SpringMethodRule field in test class [%s], " +
"but SpringMethodRule cannot be used with the SpringJUnit4ClassRunner.", testClass.getName()));
}
}
}