java.lang.Character#toChars ( )源码实例Demo

下面列出了java.lang.Character#toChars ( ) 实例代码,或者点击链接到github查看源代码,也可以在右侧发表评论。

/**
 * Get the next collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the next character in the
 * string".</p>
 * <p>This function returns the collation element that the iterator is currently
 * pointing to and then updates the internal pointer to point to the next element.
 * previous() updates the pointer first and then returns the element.  This
 * means that when you change direction while iterating (i.e., call next() and
 * then call previous(), or call previous() and then call next()), you'll get
 * back the same element twice.</p>
 *
 * @return the next collation element
 */
public int next()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }

    // if buffer contains any decomposed char values
    // return their strength orders before continuing in
    // the Normalizer's CharacterIterator.
    if (buffer != null) {
        if (expIndex < buffer.length) {
            return strengthOrder(buffer[expIndex++]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch  = text.next();

    // are we at the end of Normalizer's text?
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);
    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = ch;
        return UNMAPPEDCHARVALUE;
    }
    else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = nextContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = 0;
        value = buffer[expIndex++];
    }

    if (ordering.isSEAsianSwapping()) {
        int consonant;
        if (isThaiPreVowel(ch)) {
            consonant = text.next();
            if (isThaiBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
        if (isLaoPreVowel(ch)) {
            consonant = text.next();
            if (isLaoBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
    }

    return strengthOrder(value);
}
 
/**
 * Get the previous collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the previous character in the
 * string".</p>
 * <p>This function updates the iterator's internal pointer to point to the
 * collation element preceding the one it's currently pointing to and then
 * returns that element, while next() returns the current element and then
 * updates the pointer.  This means that when you change direction while
 * iterating (i.e., call next() and then call previous(), or call previous()
 * and then call next()), you'll get back the same element twice.</p>
 *
 * @return the previous collation element
 * @since 1.2
 */
public int previous()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }
    if (buffer != null) {
        if (expIndex > 0) {
            return strengthOrder(buffer[--expIndex]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch = text.previous();
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);

    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = UNMAPPEDCHARVALUE;
        return ch;
    } else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = prevContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = buffer.length;
        value = buffer[--expIndex];
    }

    if (ordering.isSEAsianSwapping()) {
        int vowel;
        if (isThaiBaseConsonant(ch)) {
            vowel = text.previous();
            if (isThaiPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
        if (isLaoBaseConsonant(ch)) {
            vowel = text.previous();
            if (isLaoPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
    }

    return strengthOrder(value);
}
 
/**
 * Get the next collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the next character in the
 * string".</p>
 * <p>This function returns the collation element that the iterator is currently
 * pointing to and then updates the internal pointer to point to the next element.
 * previous() updates the pointer first and then returns the element.  This
 * means that when you change direction while iterating (i.e., call next() and
 * then call previous(), or call previous() and then call next()), you'll get
 * back the same element twice.</p>
 *
 * @return the next collation element
 */
public int next()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }

    // if buffer contains any decomposed char values
    // return their strength orders before continuing in
    // the Normalizer's CharacterIterator.
    if (buffer != null) {
        if (expIndex < buffer.length) {
            return strengthOrder(buffer[expIndex++]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch  = text.next();

    // are we at the end of Normalizer's text?
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);
    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = ch;
        return UNMAPPEDCHARVALUE;
    }
    else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = nextContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = 0;
        value = buffer[expIndex++];
    }

    if (ordering.isSEAsianSwapping()) {
        int consonant;
        if (isThaiPreVowel(ch)) {
            consonant = text.next();
            if (isThaiBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
        if (isLaoPreVowel(ch)) {
            consonant = text.next();
            if (isLaoBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
    }

    return strengthOrder(value);
}
 
/**
 * Get the previous collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the previous character in the
 * string".</p>
 * <p>This function updates the iterator's internal pointer to point to the
 * collation element preceding the one it's currently pointing to and then
 * returns that element, while next() returns the current element and then
 * updates the pointer.  This means that when you change direction while
 * iterating (i.e., call next() and then call previous(), or call previous()
 * and then call next()), you'll get back the same element twice.</p>
 * @since 1.2
 */
public int previous()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }
    if (buffer != null) {
        if (expIndex > 0) {
            return strengthOrder(buffer[--expIndex]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch = text.previous();
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);

    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = UNMAPPEDCHARVALUE;
        return ch;
    } else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = prevContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = buffer.length;
        value = buffer[--expIndex];
    }

    if (ordering.isSEAsianSwapping()) {
        int vowel;
        if (isThaiBaseConsonant(ch)) {
            vowel = text.previous();
            if (isThaiPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
        if (isLaoBaseConsonant(ch)) {
            vowel = text.previous();
            if (isLaoPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码5 项目: jdk8u-dev-jdk   文件: CollationElementIterator.java
/**
 * Get the next collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the next character in the
 * string".</p>
 * <p>This function returns the collation element that the iterator is currently
 * pointing to and then updates the internal pointer to point to the next element.
 * previous() updates the pointer first and then returns the element.  This
 * means that when you change direction while iterating (i.e., call next() and
 * then call previous(), or call previous() and then call next()), you'll get
 * back the same element twice.</p>
 *
 * @return the next collation element
 */
public int next()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }

    // if buffer contains any decomposed char values
    // return their strength orders before continuing in
    // the Normalizer's CharacterIterator.
    if (buffer != null) {
        if (expIndex < buffer.length) {
            return strengthOrder(buffer[expIndex++]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch  = text.next();

    // are we at the end of Normalizer's text?
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);
    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = ch;
        return UNMAPPEDCHARVALUE;
    }
    else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = nextContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = 0;
        value = buffer[expIndex++];
    }

    if (ordering.isSEAsianSwapping()) {
        int consonant;
        if (isThaiPreVowel(ch)) {
            consonant = text.next();
            if (isThaiBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
        if (isLaoPreVowel(ch)) {
            consonant = text.next();
            if (isLaoBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码6 项目: jdk8u_jdk   文件: CollationElementIterator.java
/**
 * Get the previous collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the previous character in the
 * string".</p>
 * <p>This function updates the iterator's internal pointer to point to the
 * collation element preceding the one it's currently pointing to and then
 * returns that element, while next() returns the current element and then
 * updates the pointer.  This means that when you change direction while
 * iterating (i.e., call next() and then call previous(), or call previous()
 * and then call next()), you'll get back the same element twice.</p>
 *
 * @return the previous collation element
 * @since 1.2
 */
public int previous()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }
    if (buffer != null) {
        if (expIndex > 0) {
            return strengthOrder(buffer[--expIndex]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch = text.previous();
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);

    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = UNMAPPEDCHARVALUE;
        return ch;
    } else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = prevContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = buffer.length;
        value = buffer[--expIndex];
    }

    if (ordering.isSEAsianSwapping()) {
        int vowel;
        if (isThaiBaseConsonant(ch)) {
            vowel = text.previous();
            if (isThaiPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
        if (isLaoBaseConsonant(ch)) {
            vowel = text.previous();
            if (isLaoPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码7 项目: Java8CN   文件: CollationElementIterator.java
/**
 * Get the previous collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the previous character in the
 * string".</p>
 * <p>This function updates the iterator's internal pointer to point to the
 * collation element preceding the one it's currently pointing to and then
 * returns that element, while next() returns the current element and then
 * updates the pointer.  This means that when you change direction while
 * iterating (i.e., call next() and then call previous(), or call previous()
 * and then call next()), you'll get back the same element twice.</p>
 *
 * @return the previous collation element
 * @since 1.2
 */
public int previous()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }
    if (buffer != null) {
        if (expIndex > 0) {
            return strengthOrder(buffer[--expIndex]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch = text.previous();
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);

    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = UNMAPPEDCHARVALUE;
        return ch;
    } else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = prevContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = buffer.length;
        value = buffer[--expIndex];
    }

    if (ordering.isSEAsianSwapping()) {
        int vowel;
        if (isThaiBaseConsonant(ch)) {
            vowel = text.previous();
            if (isThaiPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
        if (isLaoBaseConsonant(ch)) {
            vowel = text.previous();
            if (isLaoPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码8 项目: jdk8u60   文件: CollationElementIterator.java
/**
 * Get the previous collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the previous character in the
 * string".</p>
 * <p>This function updates the iterator's internal pointer to point to the
 * collation element preceding the one it's currently pointing to and then
 * returns that element, while next() returns the current element and then
 * updates the pointer.  This means that when you change direction while
 * iterating (i.e., call next() and then call previous(), or call previous()
 * and then call next()), you'll get back the same element twice.</p>
 *
 * @return the previous collation element
 * @since 1.2
 */
public int previous()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }
    if (buffer != null) {
        if (expIndex > 0) {
            return strengthOrder(buffer[--expIndex]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch = text.previous();
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);

    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = UNMAPPEDCHARVALUE;
        return ch;
    } else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = prevContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = buffer.length;
        value = buffer[--expIndex];
    }

    if (ordering.isSEAsianSwapping()) {
        int vowel;
        if (isThaiBaseConsonant(ch)) {
            vowel = text.previous();
            if (isThaiPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
        if (isLaoBaseConsonant(ch)) {
            vowel = text.previous();
            if (isLaoPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
    }

    return strengthOrder(value);
}
 
/**
 * Get the next collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the next character in the
 * string".</p>
 * <p>This function returns the collation element that the iterator is currently
 * pointing to and then updates the internal pointer to point to the next element.
 * previous() updates the pointer first and then returns the element.  This
 * means that when you change direction while iterating (i.e., call next() and
 * then call previous(), or call previous() and then call next()), you'll get
 * back the same element twice.</p>
 *
 * @return the next collation element
 */
public int next()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }

    // if buffer contains any decomposed char values
    // return their strength orders before continuing in
    // the Normalizer's CharacterIterator.
    if (buffer != null) {
        if (expIndex < buffer.length) {
            return strengthOrder(buffer[expIndex++]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch  = text.next();

    // are we at the end of Normalizer's text?
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);
    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = ch;
        return UNMAPPEDCHARVALUE;
    }
    else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = nextContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = 0;
        value = buffer[expIndex++];
    }

    if (ordering.isSEAsianSwapping()) {
        int consonant;
        if (isThaiPreVowel(ch)) {
            consonant = text.next();
            if (isThaiBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
        if (isLaoPreVowel(ch)) {
            consonant = text.next();
            if (isLaoBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码10 项目: jdk8u-dev-jdk   文件: CollationElementIterator.java
/**
 * Get the previous collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the previous character in the
 * string".</p>
 * <p>This function updates the iterator's internal pointer to point to the
 * collation element preceding the one it's currently pointing to and then
 * returns that element, while next() returns the current element and then
 * updates the pointer.  This means that when you change direction while
 * iterating (i.e., call next() and then call previous(), or call previous()
 * and then call next()), you'll get back the same element twice.</p>
 *
 * @return the previous collation element
 * @since 1.2
 */
public int previous()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }
    if (buffer != null) {
        if (expIndex > 0) {
            return strengthOrder(buffer[--expIndex]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch = text.previous();
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);

    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = UNMAPPEDCHARVALUE;
        return ch;
    } else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = prevContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = buffer.length;
        value = buffer[--expIndex];
    }

    if (ordering.isSEAsianSwapping()) {
        int vowel;
        if (isThaiBaseConsonant(ch)) {
            vowel = text.previous();
            if (isThaiPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
        if (isLaoBaseConsonant(ch)) {
            vowel = text.previous();
            if (isLaoPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码11 项目: openjdk-jdk8u   文件: CollationElementIterator.java
/**
 * Get the next collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the next character in the
 * string".</p>
 * <p>This function returns the collation element that the iterator is currently
 * pointing to and then updates the internal pointer to point to the next element.
 * previous() updates the pointer first and then returns the element.  This
 * means that when you change direction while iterating (i.e., call next() and
 * then call previous(), or call previous() and then call next()), you'll get
 * back the same element twice.</p>
 *
 * @return the next collation element
 */
public int next()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }

    // if buffer contains any decomposed char values
    // return their strength orders before continuing in
    // the Normalizer's CharacterIterator.
    if (buffer != null) {
        if (expIndex < buffer.length) {
            return strengthOrder(buffer[expIndex++]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch  = text.next();

    // are we at the end of Normalizer's text?
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);
    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = ch;
        return UNMAPPEDCHARVALUE;
    }
    else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = nextContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = 0;
        value = buffer[expIndex++];
    }

    if (ordering.isSEAsianSwapping()) {
        int consonant;
        if (isThaiPreVowel(ch)) {
            consonant = text.next();
            if (isThaiBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
        if (isLaoPreVowel(ch)) {
            consonant = text.next();
            if (isLaoBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码12 项目: openjdk-jdk8u   文件: CollationElementIterator.java
/**
 * Get the previous collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the previous character in the
 * string".</p>
 * <p>This function updates the iterator's internal pointer to point to the
 * collation element preceding the one it's currently pointing to and then
 * returns that element, while next() returns the current element and then
 * updates the pointer.  This means that when you change direction while
 * iterating (i.e., call next() and then call previous(), or call previous()
 * and then call next()), you'll get back the same element twice.</p>
 *
 * @return the previous collation element
 * @since 1.2
 */
public int previous()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }
    if (buffer != null) {
        if (expIndex > 0) {
            return strengthOrder(buffer[--expIndex]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch = text.previous();
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);

    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = UNMAPPEDCHARVALUE;
        return ch;
    } else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = prevContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = buffer.length;
        value = buffer[--expIndex];
    }

    if (ordering.isSEAsianSwapping()) {
        int vowel;
        if (isThaiBaseConsonant(ch)) {
            vowel = text.previous();
            if (isThaiPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
        if (isLaoBaseConsonant(ch)) {
            vowel = text.previous();
            if (isLaoPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码13 项目: openjdk-8   文件: CollationElementIterator.java
/**
 * Get the previous collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the previous character in the
 * string".</p>
 * <p>This function updates the iterator's internal pointer to point to the
 * collation element preceding the one it's currently pointing to and then
 * returns that element, while next() returns the current element and then
 * updates the pointer.  This means that when you change direction while
 * iterating (i.e., call next() and then call previous(), or call previous()
 * and then call next()), you'll get back the same element twice.</p>
 *
 * @return the previous collation element
 * @since 1.2
 */
public int previous()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }
    if (buffer != null) {
        if (expIndex > 0) {
            return strengthOrder(buffer[--expIndex]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch = text.previous();
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);

    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = UNMAPPEDCHARVALUE;
        return ch;
    } else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = prevContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = buffer.length;
        value = buffer[--expIndex];
    }

    if (ordering.isSEAsianSwapping()) {
        int vowel;
        if (isThaiBaseConsonant(ch)) {
            vowel = text.previous();
            if (isThaiPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
        if (isLaoBaseConsonant(ch)) {
            vowel = text.previous();
            if (isLaoPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
    }

    return strengthOrder(value);
}
 
/**
 * Get the previous collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the previous character in the
 * string".</p>
 * <p>This function updates the iterator's internal pointer to point to the
 * collation element preceding the one it's currently pointing to and then
 * returns that element, while next() returns the current element and then
 * updates the pointer.  This means that when you change direction while
 * iterating (i.e., call next() and then call previous(), or call previous()
 * and then call next()), you'll get back the same element twice.</p>
 *
 * @return the previous collation element
 * @since 1.2
 */
public int previous()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }
    if (buffer != null) {
        if (expIndex > 0) {
            return strengthOrder(buffer[--expIndex]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch = text.previous();
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);

    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = UNMAPPEDCHARVALUE;
        return ch;
    } else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = prevContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = buffer.length;
        value = buffer[--expIndex];
    }

    if (ordering.isSEAsianSwapping()) {
        int vowel;
        if (isThaiBaseConsonant(ch)) {
            vowel = text.previous();
            if (isThaiPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
        if (isLaoBaseConsonant(ch)) {
            vowel = text.previous();
            if (isLaoPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码15 项目: Bytecoder   文件: CollationElementIterator.java
/**
 * Get the next collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the next character in the
 * string".</p>
 * <p>This function returns the collation element that the iterator is currently
 * pointing to and then updates the internal pointer to point to the next element.
 * previous() updates the pointer first and then returns the element.  This
 * means that when you change direction while iterating (i.e., call next() and
 * then call previous(), or call previous() and then call next()), you'll get
 * back the same element twice.</p>
 *
 * @return the next collation element
 */
public int next()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }

    // if buffer contains any decomposed char values
    // return their strength orders before continuing in
    // the Normalizer's CharacterIterator.
    if (buffer != null) {
        if (expIndex < buffer.length) {
            return strengthOrder(buffer[expIndex++]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch  = text.next();

    // are we at the end of Normalizer's text?
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);
    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = ch;
        return UNMAPPEDCHARVALUE;
    }
    else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = nextContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = 0;
        value = buffer[expIndex++];
    }

    if (ordering.isSEAsianSwapping()) {
        int consonant;
        if (isThaiPreVowel(ch)) {
            consonant = text.next();
            if (isThaiBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
        if (isLaoPreVowel(ch)) {
            consonant = text.next();
            if (isLaoBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码16 项目: jdk8u_jdk   文件: CollationElementIterator.java
/**
 * Get the next collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the next character in the
 * string".</p>
 * <p>This function returns the collation element that the iterator is currently
 * pointing to and then updates the internal pointer to point to the next element.
 * previous() updates the pointer first and then returns the element.  This
 * means that when you change direction while iterating (i.e., call next() and
 * then call previous(), or call previous() and then call next()), you'll get
 * back the same element twice.</p>
 *
 * @return the next collation element
 */
public int next()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }

    // if buffer contains any decomposed char values
    // return their strength orders before continuing in
    // the Normalizer's CharacterIterator.
    if (buffer != null) {
        if (expIndex < buffer.length) {
            return strengthOrder(buffer[expIndex++]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch  = text.next();

    // are we at the end of Normalizer's text?
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);
    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = ch;
        return UNMAPPEDCHARVALUE;
    }
    else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = nextContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = 0;
        value = buffer[expIndex++];
    }

    if (ordering.isSEAsianSwapping()) {
        int consonant;
        if (isThaiPreVowel(ch)) {
            consonant = text.next();
            if (isThaiBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
        if (isLaoPreVowel(ch)) {
            consonant = text.next();
            if (isLaoBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
    }

    return strengthOrder(value);
}
 
/**
 * Get the next collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the next character in the
 * string".</p>
 * <p>This function returns the collation element that the iterator is currently
 * pointing to and then updates the internal pointer to point to the next element.
 * previous() updates the pointer first and then returns the element.  This
 * means that when you change direction while iterating (i.e., call next() and
 * then call previous(), or call previous() and then call next()), you'll get
 * back the same element twice.</p>
 */
public int next()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }

    // if buffer contains any decomposed char values
    // return their strength orders before continuing in
    // the Normalizer's CharacterIterator.
    if (buffer != null) {
        if (expIndex < buffer.length) {
            return strengthOrder(buffer[expIndex++]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch  = text.next();

    // are we at the end of Normalizer's text?
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);
    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = ch;
        return UNMAPPEDCHARVALUE;
    }
    else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = nextContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = 0;
        value = buffer[expIndex++];
    }

    if (ordering.isSEAsianSwapping()) {
        int consonant;
        if (isThaiPreVowel(ch)) {
            consonant = text.next();
            if (isThaiBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
        if (isLaoPreVowel(ch)) {
            consonant = text.next();
            if (isLaoBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码18 项目: openjdk-jdk9   文件: CollationElementIterator.java
/**
 * Get the previous collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the previous character in the
 * string".</p>
 * <p>This function updates the iterator's internal pointer to point to the
 * collation element preceding the one it's currently pointing to and then
 * returns that element, while next() returns the current element and then
 * updates the pointer.  This means that when you change direction while
 * iterating (i.e., call next() and then call previous(), or call previous()
 * and then call next()), you'll get back the same element twice.</p>
 *
 * @return the previous collation element
 * @since 1.2
 */
public int previous()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }
    if (buffer != null) {
        if (expIndex > 0) {
            return strengthOrder(buffer[--expIndex]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch = text.previous();
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);

    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = UNMAPPEDCHARVALUE;
        return ch;
    } else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = prevContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = buffer.length;
        value = buffer[--expIndex];
    }

    if (ordering.isSEAsianSwapping()) {
        int vowel;
        if (isThaiBaseConsonant(ch)) {
            vowel = text.previous();
            if (isThaiPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
        if (isLaoBaseConsonant(ch)) {
            vowel = text.previous();
            if (isLaoPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码19 项目: hottub   文件: CollationElementIterator.java
/**
 * Get the next collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the next character in the
 * string".</p>
 * <p>This function returns the collation element that the iterator is currently
 * pointing to and then updates the internal pointer to point to the next element.
 * previous() updates the pointer first and then returns the element.  This
 * means that when you change direction while iterating (i.e., call next() and
 * then call previous(), or call previous() and then call next()), you'll get
 * back the same element twice.</p>
 *
 * @return the next collation element
 */
public int next()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }

    // if buffer contains any decomposed char values
    // return their strength orders before continuing in
    // the Normalizer's CharacterIterator.
    if (buffer != null) {
        if (expIndex < buffer.length) {
            return strengthOrder(buffer[expIndex++]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch  = text.next();

    // are we at the end of Normalizer's text?
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);
    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = ch;
        return UNMAPPEDCHARVALUE;
    }
    else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = nextContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = 0;
        value = buffer[expIndex++];
    }

    if (ordering.isSEAsianSwapping()) {
        int consonant;
        if (isThaiPreVowel(ch)) {
            consonant = text.next();
            if (isThaiBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
        if (isLaoPreVowel(ch)) {
            consonant = text.next();
            if (isLaoBaseConsonant(consonant)) {
                buffer = makeReorderedBuffer(consonant, value, buffer, true);
                value = buffer[0];
                expIndex = 1;
            } else if (consonant != NormalizerBase.DONE) {
                text.previous();
            }
        }
    }

    return strengthOrder(value);
}
 
源代码20 项目: jdk8u-jdk   文件: CollationElementIterator.java
/**
 * Get the previous collation element in the string.  <p>This iterator iterates
 * over a sequence of collation elements that were built from the string.
 * Because there isn't necessarily a one-to-one mapping from characters to
 * collation elements, this doesn't mean the same thing as "return the
 * collation element [or ordering priority] of the previous character in the
 * string".</p>
 * <p>This function updates the iterator's internal pointer to point to the
 * collation element preceding the one it's currently pointing to and then
 * returns that element, while next() returns the current element and then
 * updates the pointer.  This means that when you change direction while
 * iterating (i.e., call next() and then call previous(), or call previous()
 * and then call next()), you'll get back the same element twice.</p>
 *
 * @return the previous collation element
 * @since 1.2
 */
public int previous()
{
    if (text == null) {
        return NULLORDER;
    }
    NormalizerBase.Mode textMode = text.getMode();
    // convert the owner's mode to something the Normalizer understands
    NormalizerBase.Mode ownerMode =
        CollatorUtilities.toNormalizerMode(owner.getDecomposition());
    if (textMode != ownerMode) {
        text.setMode(ownerMode);
    }
    if (buffer != null) {
        if (expIndex > 0) {
            return strengthOrder(buffer[--expIndex]);
        } else {
            buffer = null;
            expIndex = 0;
        }
    } else if (swapOrder != 0) {
        if (Character.isSupplementaryCodePoint(swapOrder)) {
            char[] chars = Character.toChars(swapOrder);
            swapOrder = chars[1];
            return chars[0] << 16;
        }
        int order = swapOrder << 16;
        swapOrder = 0;
        return order;
    }
    int ch = text.previous();
    if (ch == NormalizerBase.DONE) {
        return NULLORDER;
    }

    int value = ordering.getUnicodeOrder(ch);

    if (value == RuleBasedCollator.UNMAPPED) {
        swapOrder = UNMAPPEDCHARVALUE;
        return ch;
    } else if (value >= RuleBasedCollator.CONTRACTCHARINDEX) {
        value = prevContractChar(ch);
    }
    if (value >= RuleBasedCollator.EXPANDCHARINDEX) {
        buffer = ordering.getExpandValueList(value);
        expIndex = buffer.length;
        value = buffer[--expIndex];
    }

    if (ordering.isSEAsianSwapping()) {
        int vowel;
        if (isThaiBaseConsonant(ch)) {
            vowel = text.previous();
            if (isThaiPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
        if (isLaoBaseConsonant(ch)) {
            vowel = text.previous();
            if (isLaoPreVowel(vowel)) {
                buffer = makeReorderedBuffer(vowel, value, buffer, false);
                expIndex = buffer.length - 1;
                value = buffer[expIndex];
            } else {
                text.next();
            }
        }
    }

    return strengthOrder(value);
}